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UPSC Prelims 1988 · World Geography · Earth in Space
The period of one revolution of a geostationary satellite is
- (a) 24 hours
- (b) 30 days
- (c) 365 days
- (d) 48 hours
Show the answer and explanation
Answer: (a) 24 hours
A geostationary satellite orbits once in ~24 hours (one sidereal day) at ~36,000 km, so it stays over one spot.
The idea
A geostationary satellite must move around Earth at the same angular rate as Earth turns. Its orbit must also be circular, above the equator and in the same direction as Earth’s rotation. Together these conditions keep it above one ground location.
Place satellite in a circular equatorial orbit → Make it travel west to east → Match its orbital period to Earth’s sidereal rotation → Satellite and ground turn at the same angular rate → Satellite stays over one longitude
Elimination technique
Remaining fixed above a ground point requires matching Earth’s daily rotation, so month-long, year-long and two-day periods can be rejected.
Also know
The exact matching period is one sidereal day, about 23 hours 56 minutes; 24 hours is the rounded exam answer. A geosynchronous orbit matches that period but need not keep a satellite over one point. Polar satellites pass over changing regions and are useful for mapping and Earth observation.
🔒 GEO: 35,786 km, over the equator, 24 h orbit (INSAT/GSAT).
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